Tentukan nilai x yang memenuhi persamaan eksponen :
Penjelasan dengan langkah-langkah:
soal 1
[tex](x - 3 {)}^{ {x}^{2} - 3x - 2 } = {x}^{2} - 6x + 9 \\ (x - 3)log_{ {x }^{2} - 6x + 9 } = {x}^{2} + 3x - 2 \\ (x - 3) log_{(x - 3 {)}^{2}} = {x}^{2} + 3x - 2 \\ 2 \times 1 = {x}^{2} + 3x - 2 \\ {x }^{2} + 3x - 4 = 0 \\ (x + 4)(x - 1) \\ \\ x = - 4 \\ x = 1[/tex]
soal 2
[tex](x - 7 {)}^{ {x}^{2} - 3x - 10} = 1 \\ (x - 7) log_{1} = {x}^{2} - 3x - 10[/tex]
karena
[tex]a log(1) = 0[/tex]
maka berlaku
[tex]0 = {x}^{2} - 3x - 10 \\ {x}^{2} - 3x - 10 = 0 \\ (x - 5)(x + 2) \\ \\ x = 5 \\ x = - 2[/tex]
terima kasih waktunya^-^
semoga membantu
[answer.2.content]
